49x^2+84x-36=0

Solution for 49x^2+84x-36=0 equation:

49x^2+84x-36=0

a = 49; b = 84; c = -36;
Δ = b2-4ac
Δ = 842-4·49·(-36)
Δ = 14112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14112}=\sqrt{7056*2}=\sqrt{7056}*\sqrt{2}=84\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-84\sqrt{2}}{2*49}=\frac{-84-84\sqrt{2}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+84\sqrt{2}}{2*49}=\frac{-84+84\sqrt{2}}{98}
$